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Post by bbff1234 on Jul 4, 2015 22:19:57 GMT
Title says it all. Has anyone constructed a set bounded above in F without a least upper bound?
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Post by KBeal on Jul 6, 2015 0:19:44 GMT
look at the sign (+ or -) of elts of F that are not real numbers, say f(x)=x, or f(x)=x^2, and f(x)=1/x or f(x)=1/{x^2}
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Post by Guest on Jul 6, 2015 3:46:12 GMT
note that for all n, x^{n+1}>x^n
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